Kinematics
Motion in a straight line and plane, projectile motion
Key Concepts
- Displacement is a vector; distance is a scalar
- Uniform acceleration: equations of motion apply directly
- Projectile motion: horizontal (constant velocity) + vertical (free fall)
- Relative velocity: v_AB = v_A − v_B
- For maximum range of projectile: θ = 45°
Important Formulae
| First equation of motion | v = u + at |
| Second equation of motion | s = ut + ½at² |
| Third equation of motion | v² = u² + 2as |
| Range of projectile | R = u²sin2θ / g |
| Maximum height | H = u²sin²θ / 2g |
| Time of flight | T = 2u sinθ / g |
Quick Tips
- At maximum height of a projectile, vertical velocity = 0; horizontal velocity is unchanged.
- For equal ranges: angles θ and (90° − θ) give the same range.
- Area under velocity–time graph = displacement; slope = acceleration.
Sample Practice Questions
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The time of flight of a projectile on a horizontal plane is 2 s. Maximum height reached (g = 10 m/s²):
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Answer: 5 m
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Two trains A and B are moving at 60 km/h and 40 km/h in the same direction. Relative velocity of A with respect to B:
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Answer: 20 km/h
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Two objects are thrown from the same point with the same speed but at angles 30° and 60°. Their ranges are:
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Answer: Equal
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A particle has initial velocity 3i + 4j m/s. Its speed is:
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Answer: 5 m/s
Practice Questions
Practice 20 randomly selected NEET questions on Kinematics. Answers are revealed after each question.
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What are the key concepts in Kinematics for NEET?
Displacement is a vector; distance is a scalar; Uniform acceleration: equations of motion apply directly; Projectile motion: horizontal (constant velocity) + vertical (free fall); Relative velocity: v_AB = v_A − v_B; For maximum range of projectile: θ = 45°.
Which formulae are important for Kinematics in NEET?
First equation of motion: v = u + at; Second equation of motion: s = ut + ½at²; Third equation of motion: v² = u² + 2as; Range of projectile: R = u²sin2θ / g; Maximum height: H = u²sin²θ / 2g; Time of flight: T = 2u sinθ / g.
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