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Coordinate Geometry

Distance, midpoint, slopes, conic sections, and loci

Key Concepts

  • Distance and section formulas locate points
  • The shoelace formula gives a polygon's area from its vertices
  • Lines and circles have standard coordinate equations
  • Collinearity and concurrency can be tested algebraically

Important Formulae

Distance √((x₂−x₁)² + (y₂−y₁)²)
Triangle area (shoelace) ½ |x₁(y₂−y₃) + x₂(y₃−y₁) + x₃(y₁−y₂)|
Section formula ((mx₂+nx₁)/(m+n), (my₂+ny₁)/(m+n))

Quick Tips

  • Three points are collinear if the triangle area they form is zero.
  • Placing the figure with a convenient origin simplifies the algebra.

Sample Practice Questions

  1. The locus of points equidistant from (2,0) and (-2,0) is:

    • x = 2
    • y = 2
    • The y-axis (x = 0)
    • The x-axis (y = 0)
    Show answer

    Answer: The y-axis (x = 0)

  2. A circle passes through (1,0), (-1,0), (0,1). Its centre is:

    • (0, 1)
    • (1, 0)
    • (0, 0)
    • Cannot determine
    Show answer

    Answer: (0, 0)

  3. How many lattice points (integer coordinates) are inside the circle x² + y² = 5?

    • 4
    • 8
    • 9
    • 12
    Show answer

    Answer: 9

  4. Three points A, B, C are collinear when the area of triangle ABC is:

    • 0
    • 1
    • Negative
    • Cannot be 0
    Show answer

    Answer: 0

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Practice Questions

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Frequently Asked Questions

What are the key concepts in Coordinate Geometry for PRMO?

Distance and section formulas locate points; The shoelace formula gives a polygon's area from its vertices; Lines and circles have standard coordinate equations; Collinearity and concurrency can be tested algebraically.

Which formulae are important for Coordinate Geometry in PRMO?

Distance: √((x₂−x₁)² + (y₂−y₁)²); Triangle area (shoelace): ½ |x₁(y₂−y₃) + x₂(y₃−y₁) + x₃(y₁−y₂)|; Section formula: ((mx₂+nx₁)/(m+n), (my₂+ny₁)/(m+n)).

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